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Home » Chemistry Homework Help » Organic Chemistsry » Degree of Dissociation
Degree of Dissociation
It is defined as the fraction of total molecules which dissociate into simpler molecules or ions.

In order to calculate the degree of dissociation let us suppose that each element of a substance of dissociation gives m particles and is the degree of dissociation. Then for each mole of the substance dissolved.

Number of moles dissociated =

Number of moles left undissociated = 1 –

Total number of particles at equilibrium = (1 – ) + m

Van’t Hoff’s factor = (observed value of colligative property)/(calculated value of colligative property)

Or, i = (number of particles after dissociation)/(number of particles before dissociation)

= 1 + (m – 1)

Or,

Since, i = Mn/Mo

(Mn = normal molar mass, Mo = observed molar mass)

The expressions can be put together as



For the electrolytes of the type AB, such as NaCl, KCl etc. the number of particles in solution i.e. m = 2.

=I – 1.

Similarly, for the electrolytes of the type AB2, like CaCl2, the value of m = 3 and hence,

= (i-1)/2.

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