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Dimensional Formulae
All physical quantities can be expressed in terms of seven fundamental units called seven dimensions of physical world. Thus, a physical quantity can be expressed in terms of these fundamental units or dimensions. A physical quantity expressed in terms of fundamental dimension is termed as dimensional formula of that physical quantity.
The dimensional formulae of force, energy, compressibility and capacity of a capacitor, are [MLT-2],
[ML2T2], [M-1 LT2) and [M-1L-2T4A2] respectively,
Applications of dimensional analysis
To find the unit of a physical quantity
For example, G = [M-1L3T2]. Its SI unit is m3kg-1s-2 or Nm2 kg-2
To convert a physical quantity from on system of units to another system of units
It is based on the fact that
n1u1 = n2u2
We illustrate by an example. Let us convert g from SI system to FPS system
We know [g] = [Lt2]
n2 = n1 [L1/L2] [T1/T2]-2 1 ft = 30.48 cm
= 9.8 [100/30.48] [1/1]-2 1 m = 100 cm
= 32.2 fts-2
To check the correctness of a given physical relation
It is based on principle of homogeneity that is, the dimensions on two sides be same for a given relation.
For example
F = mv2/r where, [F] = [MLT-2]; [v] [LT-1]
Therefore, LHS = [MLT-2]
RHS = [M] {LT-1]2 / [L] = [MLT-2]
To derive a relation let us consider an example. Derive plank’s length in terms of G, c and h
L = f (G, e, h) L = KGx cy hz
[L] = [M-1 L3 T-2] x [LT-2] y [ML2 T-1] z
-x + z =), 3x + y + 2z = 1 and – 2x –y –z = 0
X = ½, y = -3/2 and z = 1/2
Thus, L = K √GH/c3.
If K = 1 then L ≃ 10-35 m.
The importance of plank’s length is yet to be established.
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The dimensional formulae of force, energy, compressibility and capacity of a capacitor, are [MLT-2],
[ML2T2], [M-1 LT2) and [M-1L-2T4A2] respectively,
Applications of dimensional analysis
To find the unit of a physical quantity
For example, G = [M-1L3T2]. Its SI unit is m3kg-1s-2 or Nm2 kg-2
To convert a physical quantity from on system of units to another system of units
It is based on the fact that
n1u1 = n2u2
We illustrate by an example. Let us convert g from SI system to FPS system
We know [g] = [Lt2]
n2 = n1 [L1/L2] [T1/T2]-2 1 ft = 30.48 cm
= 9.8 [100/30.48] [1/1]-2 1 m = 100 cm
= 32.2 fts-2
To check the correctness of a given physical relation
It is based on principle of homogeneity that is, the dimensions on two sides be same for a given relation.
For example
F = mv2/r where, [F] = [MLT-2]; [v] [LT-1]
Therefore, LHS = [MLT-2]
RHS = [M] {LT-1]2 / [L] = [MLT-2]
To derive a relation let us consider an example. Derive plank’s length in terms of G, c and h
L = f (G, e, h) L = KGx cy hz
[L] = [M-1 L3 T-2] x [LT-2] y [ML2 T-1] z
-x + z =), 3x + y + 2z = 1 and – 2x –y –z = 0
X = ½, y = -3/2 and z = 1/2
Thus, L = K √GH/c3.
If K = 1 then L ≃ 10-35 m.
The importance of plank’s length is yet to be established.
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